If you want to solve the crypt or the gallery puzzle with the fewest clicks, the same method applies, but it's a bit trickier for the gallery.

In fact, for both puzzles, I will explain in what circumstance it is required to click the center, a given corner, or a given edge. Then you just click on those, possibly twice.

CRYPT:

Every piece has a solving-pattern that you need to know. So up to rotation, you need to know three solving-patterns. Do not confuse those with the patterns you get from clicking on them.

IN THEORY:

CENTER:

The solving-pattern for the center piece is:

XOX  
OXO  
XOX  

or

101
010
101

whichever you prefer. Count the number of OPEN coffins in the X (i.e. 1)-Positions. If it's odd, click the center coffin. If it's even, don't.

CORNER:

The solving pattern for the top left corner is:

XOX
OOX
XXO

So if the number of OPEN coffins in the X-Positions is odd, click the top left corner, otherwise don't.

Rotate the pattern to each corner to determine if other corners need to be hit.

EDGE:

The solving pattern for the top edge is:

XXX
XXX
OOO

so if the number of OPEN coffins in the X-Positions is odd, click the top edge, otherwise don't.

IN PRACTICE:

Solving the edges and the center is a LOT easier than solving the corners. So solve the center and the edges first, then click all the edge coffins that are open.

GALLERY:

[BLA BLA INTRODUCTION ABOUT MOD 3]

Skin=0, Green=1, Red=2

IN THEORY:

CENTER: Add up all numbers that are not the center. If it's 1, click once. If it's 2, click twice. In other words, the solving pattern is

111
101
111

CORNER: For the top left corner, add all the numbers that aren't the bottom and right edge, and add the bottom right corner again. The solving pattern is hence:

111
110
102

click once if 1, twice if 2

EDGES: For the top edge, add the piece itself, the row below, and the bottom row twice. The patterns is:

010
111
222

If it's 1 click once, if it's 2 click twice.

IN PRACTICE:

Solve the center and the corners first, then click the green edges once, the red edges twice.

Don't think in numbers. Think ONLY in colours and abuse properties of mod 3 calculations, like 0=1+1+1=2+2+2=1+2=2+1. In other words, the following patterns cancel each other out (when in a 1-Position):

• 3 green pieces
• 3 red pieces
• a red and a green piece.

Furthermore: 0=1x2+1x1 =2x2+2x1 =Ax2+Ax1 In other words, a piece in the 2-Position will cancel with a piece in the 1-Position of the same colour.

Finally, as it comes up all the time: 2+2=1, 1+1=2. That means 2 red pieces behave like a green piecee, 2 green pieces behave like a red one.

Guessing the last corner: When the center and all corners are done, the center piece must be a skin piece, because only edges need to be pressed afterwards. In other words, when the center and EXACTLY 3 out of 4 corners are solved, the number of clicks in the final corner IS the center colour.

Guessing when all corner are set: When the center is set, and all corners are done, the center piece must be skin. Therefore, when setting the corners and the centerpiece is SKIN, quickly check if the edges are solvable. That is trivial if (at least) one of the edges is SKIN colour. If not, ONLY the following patterns are possible, up to symmetry:

RGR
GSG
RGR

SRS
GSG
RGR

GRS
RSG
SGR

SRS
GSG
SRS

GRG
RSR
SGS

GRG
RSR
GRG

Note how there's no two equal neighbouring colours. (neighbouring meaning neigbours on the square boundary) In particular, between the edges X and Z the corner is always Y accodring to this table:

X|Y|Z

G|R|G G|S|R R|S|G R|G|R